Topic: Equilibria equation (Read 5255 times)

astrapw · « **on:** October 21, 2006, 09:48:39 PM »

How would you write a balanced equilibria equation for benzoic acid(C5H5COOH) and NaOH?

Thanks

Yggdrasil · « **Reply #1 on:** October 21, 2006, 09:53:47 PM »

What kind of reaction would you expect between benzoic acid and NaOH, a base?

astrapw · « **Reply #2 on:** October 21, 2006, 10:04:52 PM »

A salt??? I would have thought part of the product side to contain water.

Yggdrasil · « **Reply #3 on:** October 21, 2006, 10:12:11 PM »

acid + base --> salt + water

astrapw · « **Reply #4 on:** October 21, 2006, 10:17:41 PM »

I understand the salt + H2O, but still am unsure how to write the equation.

C6H5COOH+NaOH <-----> C6H5COONA+H2O??

Yggdrasil · « **Reply #5 on:** October 21, 2006, 10:22:23 PM »

You know more than you think. Your answer is correct.

Side note: the C₆H₅COONa is sodium benzoate, a common food preservative.