983,98g of a polymer C_{2n+2}H_{4n+6}O_{n+1} solid are brought to gas form at 442,71K. the volume occupied by the gas at 0,416546 bar is 12,4 dm^{3}. calculate the number of monomers which are part of the polymer.

by using the ideal gas formula i get the n = 0,14 mol, then i've calculated the monomer's weight putting n = 0 and i obtained 46 g*mol^{-1}. dividing the polymer's weight per the mole number i found i get MP = 7028,42 gmol^{-1}. by dividing the polymer's molecular mass with the monomer's molecular mass i get n=152,8 but the result should be 158.