[lad03]

I got this problem wrong on my quiz:
A 208.9 lb object displaces 2.73 gallons of water when submerged.  What is the density of the object in g/L? (1 gal = 3.79 L, 1 kg = 2.20 lbs) Input your answer in scientific notation (use "E" for x10^, example: 1.0E2, you do not need units)

Selected Answer:   
Incorrect 9.22E2
Correct Answer:   
Correct 9.18E3 ± 5

What did I do wrong and what is the deal with the plus or minus 5 at the end of the correct answer?

[Orcio_87]

9.177 x 10³ = 9.177E3 is the correct answer.

±5 is the measurement uncertainty, that means - someone calculated that density has value from 9175 to 9185 g/L.

[Borek]

9.177 x 10³ = 9.177E3 is the correct answer.

Volume is given to three significant digits, no wonder the answer was rounded down to 9.18e3.

Giving ±5 as the measurement uncertainty looks unfounded (but I agree it looks like that was the intention).

[lad03]

9.177 x 10³ = 9.177E3 is the correct answer.

Volume is given to three significant digits, no wonder the answer was rounded down to 9.18e3.

Giving ±5 as the measurement uncertainty looks unfounded (but I agree it looks like that was the intention).

Ah, I see. Thank you! How was it E3 and not E2? Here is my work...

208.9 lb x (1kg/2.20lb) x (10^3 g/1 kg) = 9495.545454 g
2.73 gal x (3.79 L/1 gal) = 10.3467 L
I then rounded to 3 significant figures to each of those values, getting 9.50E3 g and 10.3 L
9.50E3 g/10.3 L = 9.22E2

[mjc123]

first line gives 94,955 g

[lad03]

first line gives 94,955 g

Ohhh, okay thank you!

[sjb]

I'd also consider holding a few more sf in the conversions to mass and volume before dividing; just in case you're near a boundary.