April 24, 2024, 12:53:54 PM
Forum Rules: Read This Before Posting


Topic: Neutralisation and Na2SO4  (Read 749 times)

0 Members and 1 Guest are viewing this topic.

Offline Jenzer

  • Very New Member
  • *
  • Posts: 1
  • Mole Snacks: +0/-0
Neutralisation and Na2SO4
« on: September 22, 2021, 07:01:21 PM »
For the neutralisation equation:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

I don't understand where the "2" in the salt product for Na has come from?

If you could point out what topic I need to study for this it'd be much appreciated.

Thank you

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27662
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Neutralisation and Na2SO4
« Reply #1 on: September 23, 2021, 02:54:24 AM »
So basically you are asking why given compound has a formula that it has?

Why do you accept H2SO4, but Na2SO4 raises a question?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Meter

  • Full Member
  • ****
  • Posts: 254
  • Mole Snacks: +14/-3
  • Take what I say with a grain of salt
Re: Neutralisation and Na2SO4
« Reply #2 on: September 23, 2021, 08:00:04 AM »
The "Na2" comes from the 2 moles of NaOH.

Na2SO4 is somewhat soluble in aqueous solutions, so you would have an equilibrium of the solid salt and the dissolved free ions of the salt.

Sponsored Links