Oops, I lied about #1, it is incorrect.
There are 3 oxygens per NaHCO3.
1) 0.565g (your first answer I accidentally typed as correct was wrong, you just found the % of one oxygen molecule, not all 3), watch your significant figures on this one, it is very important here to illustrate you calculated it correct
2) 2.09 mol (this is just mass/MW)
3)448.6 (notice something about your answer and this one? You are off by a factor 2, you did not balance the equation first)
5) 2.38e24 ( First find moles, and for every mole you have 6.022e23 molecules)
6) 0.789 mol LiF (20.5g) and 1.37 mol Li (9.5g) are left over (You must first convert mass to moles, write a balanced equation and find out which one is your limiting reagent), you can also then check your self after calculating it by converting them to grams (as I did) because you know the masses also have to balance, so 20.5+9.5 = 30 (which is what we started with). Note: your teacher probably wants the answer for that in mass, but you can put both to be sure.