[candiishop]

A cell can be prepared from copper and tin. What is the E° cell for the cell that forms from the following half reactions?
Cu2+(aq) + 2e-  Cu(s) E° = 0.35 V
Sn4+(aq) + 2e-  Sn2+(aq) E° = 0.13 V

 
a) 0.48 V
 
b) 0.22 V
 
c) -0.48 V
 
d) -0.22 V

Sorry.. im so lost in electrochemistry.

E° cellf = E° cathode - E° anode

Ok... looking at the Cu2+ half equation.. the voltage is greater.. so it is an oxidising reagent, more tendency and is reduced

So im guessing the answer is D?

E° cell= 0.13- 035

[candiishop]

Hold on.. is it 0.35V + 0.13V = 0.48V?

I'm confused.. when do we use the Ecell= Ecathode- Eanode forumula? Thanks heaps

[enahs]

I'm confused.. when do we use the Ecell= Ecathode- Eanode forumula? Thanks heaps

You use it now.


Cathode <-> Reduction
Anode <-> Oxidation