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Topic: Cyclohexanol (C6H11OH) + K2Cr2O7  (Read 1015 times)

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Offline shook0

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Cyclohexanol (C6H11OH) + K2Cr2O7
« on: February 02, 2022, 02:05:44 PM »
Hi, I'm supposed to set up a reaction between Cyclohexanol (I'm German, so I'm not sure if this spelling is correct in English) and K2Cr2O7. I thought it's a classical oxidation, however, the oxidation numbers don't change if I see it correctly. Can anybody help me please?

 C6H11OH + K2Cr2O7 :rarrow:  ?

Offline Babcock_Hall

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Re: Cyclohexanol (C6H11OH) + K2Cr2O7
« Reply #1 on: February 02, 2022, 02:17:02 PM »
Can you show us what your oxidation numbers are?

Offline shook0

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Re: Cyclohexanol (C6H11OH) + K2Cr2O7
« Reply #2 on: February 02, 2022, 03:23:14 PM »
C6H11OH = C: +II; H +I; O: -II
The same applies to C6H11OOH

Offline Babcock_Hall

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Re: Cyclohexanol (C6H11OH) + K2Cr2O7
« Reply #3 on: February 02, 2022, 03:58:31 PM »
Can you think of a different organic product?

Offline Borek

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Re: Cyclohexanol (C6H11OH) + K2Cr2O7
« Reply #4 on: February 02, 2022, 04:38:06 PM »
C6H11OH = C: +II; H +I; O: -II
The same applies to C6H11OOH

No, ROOH contains an oxygen-oxygen bond, so these O don't have oxidation numbers of -2.

Not that it is an expected product of an alcohol oxidation.
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