hi, can someone help me with this redox reaction?
CuS + NO
-3 + H
+ Cu
2+ + S + NO + H
2O
i used the semi-reaction method and i obteined
3CuS + 8H
+ + 2NO
-3 3Cu
2+ + 3S +2no + 4H
2O
Then i have to write the molecular form and here is my problem
the solution of this exercise is:
3CuS + 8HNO
3 3Cu(NO
3)
2 + 3S + 2NO +4H
2O
I don't understand how we arrive at 3Cu(NO
3)
2the solution said to add 6NO
3- in the products but i don't understand why...