November 27, 2022, 03:04:55 AM
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Topic: Adding 2 different solutions  (Read 545 times)

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Offline Smileylover1

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Adding 2 different solutions
« on: March 23, 2022, 02:55:37 AM »
I've been struggling a lot with this question:

0.0015L of H2SO4 is added to 0.0237L of NAOH, which has a molar concentration of M= 0,147 mol/L
What's the concentration of the H2SO4 solution?

I tried solving it with the M1V1 = M2V2 formula, which probably is the wrong way to do this. So far I've only been able to solve solution/dilution problems for solutions of the same compound.

Thanks for any help

Offline Borek

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Re: Adding 2 different solutions
« Reply #1 on: March 23, 2022, 03:57:59 AM »
What happens when you mix sulfuric acid and sodium hydroxide?

Note: question is either incomplete, or you are expected to assume 0.0015 L of a _pure_ sulfuric acid, if so, you need to look for some additional information about its properties, not given in the question.
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Offline Aldebaran

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Re: Adding 2 different solutions
« Reply #2 on: March 23, 2022, 09:17:07 AM »
Write the balanced equation for the reaction . This gives you the ratio of moles of each of the reactants. You can work out how many moles of sodium hydroxide is being used because you are given volume and concentration. Use the ratio from the equation to work out how many moles of acid are used . You are given the volume of acid solution so moles per volume gives you concentration of the acid.

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