October 07, 2022, 02:08:47 AM
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Topic: (Resonance Structures): Is this a trick question?  (Read 619 times)

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Offline RobertWithers

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(Resonance Structures): Is this a trick question?
« on: April 11, 2022, 09:46:25 PM »
Hello all. So I am supposed to write the resonance structures for N2O42-.

This is the logic I used:
N - 5 valence e- times 2 = 10
O - 6 valence e- times 4 = 24
Given Charge of -2:          +2
= 36

I've tried arrangements in which there are two double bonds between N=O but those don't add up to 36 e-. The only way I could reach 36 was with a double bond between the nitrogens and single bonds between the oxygens and nitrogens.

However this would only yield one resonance structure of I am not mistaken as the double bond cannot move?

I've spent far too much time worrying that I have made a stupid mistake so I've come here for guidance. Any advice would be appreciated.

-Rob

Offline Hunter2

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Re: (Resonance Structures): Is this a trick question?
« Reply #1 on: April 12, 2022, 01:53:54 AM »
I think it is not existing with 2 negative charge. The neutral molecule can be found.
https://upload.wikimedia.org/wikipedia/commons/thumb/4/4e/Distickstofftetroxid.svg/1200px-Distickstofftetroxid.svg.png

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