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Which will react faster in E2 / SN1

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sharbeldam:
" so for the cis t-Bu/Br cyclohexane, when t-Bu is eq, Br is axial and E2 is fast.  For trans t-Bu/Br cyclohexane with t-Bu eq the Br is eq and elimination is slow. "

Thank you so my assumption was wrong, i cant draw both molecules with Br in axial since that means that molecule A would have a big group in the axial position, so basically A molecule is very confused " Do I want my Br axial so E2 can occur or do I want my big T-bu group in equatorial because its more stable " and t-bu in equatorial would win the argument and hence Br would be in equatorial too and E2 would be slow.

B>A

I GET IT , THANKS A LOT!!

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