Hello everyone, I need some help solving the problem below.
You are planning a large clambake for the upcoming weekend. You will need to heat
22.0 gallons of water from 15.0°C to 90.0°C by burning propane gas, C3H8. If the heat of combustion
of the propane gas is -2225 kJ/mol, how many liters of propane gas, stored at 25.0°C and 30.0 atm
in a tank would be needed to heat the 22.0 gallons of water?