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thermal analysis cerium nitrate ammonium

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--- Quote from: Orcio_87 on May 10, 2022, 04:05:52 PM ---You have two peaks on the graph, not just one. So it is not only one reaction that you are looking for.

--- End quote ---

Perhaps I am missing something, but for the composition it should be enough to compare initial state ((NH4)2Ce(NO3)m) with the final one (CeO2), path nor intermediates don't matter.

You don't have to take note of the intermediates to calculate the number of molecule of nitrate.
Well if we add to  ((NH4)2Ce(NO3)m) 3 molecules of H20, we have approximately the mass loss at the end of the decomposition. I don't know if this salt could be under the crystallized form.

Crystal water can be always a factor, no doubt about it. Thing is, in the case of hydrates such water is typically clearly stated in the formula.

Loosing this water should be visible as a step on the curve. Does the water mass fit the first mass loss step?


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