August 09, 2022, 01:43:04 AM
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Topic: Buffer preparation calculations  (Read 1186 times)

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Offline SamanthaMcOw

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Buffer preparation calculations
« on: June 27, 2022, 07:34:29 AM »
Hi Folks!

I would like to know if I am thinking correctly when solving this problem. I have to prepare 80mM ammonium formate (1L volume), MW 63.03 g / mol.

I calculated it this way:

(0,08 M* 1L)/63,03 g/mol= 0,13 g

So I need to weight 0,13 g into 1 L of mili water....is that correct, weight seems a bit low

Offline Aldebaran

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Re: Buffer preparation calculations
« Reply #1 on: June 27, 2022, 10:18:39 AM »
I haven’t checked your Mr but assuming it’s correct at 63.03 then you’d need 63.03g per litre for a molar solution. Thus for 0.08 molar you would need ….?

Offline Babcock_Hall

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Re: Buffer preparation calculations
« Reply #2 on: June 27, 2022, 11:22:59 AM »
Think about units cancellation.

Offline SamanthaMcOw

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Re: Buffer preparation calculations
« Reply #3 on: June 28, 2022, 04:29:28 AM »
I haven’t checked your Mr but assuming it’s correct at 63.03 then you’d need 63.03g per litre for a molar solution. Thus for 0.08 molar you would need ….?

then I will need 5,04 g/L

Is that correct :)?

Offline Borek

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Re: Buffer preparation calculations
« Reply #4 on: June 28, 2022, 06:42:35 AM »
Looks OK now.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info, pH-meter.info

Offline Aldebaran

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Re: Buffer preparation calculations
« Reply #5 on: June 28, 2022, 11:40:58 AM »
Correct!

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