November 30, 2023, 08:05:30 PM
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### Topic: Why in the equation E=v/d E units are coulomb  (Read 1145 times)

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#### darkwizard267787

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• Mole Snacks: +0/-0 ##### Why in the equation E=v/d E units are coulomb
« on: October 28, 2022, 03:45:02 AM »
Hi,
I don't understand how volt/m=C.
because C is A*s
and v is J/C

I'm probably just doing it wrong, can someone explain me?

#### Hunter2

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• Gender: • Vena Lausa moris pax drux bis totis ##### Re: Why in the equation E=v/d E units are coulomb
« Reply #1 on: October 28, 2022, 04:49:15 AM »
In which context is this all.v is it speed? Or what. V is volume.
What is m?  Mass?

J/C = U => J = Ws = VAs and C = As => VAs/As = V voltage.

#### Borek ##### Re: Why in the equation E=v/d E units are coulomb
« Reply #2 on: October 28, 2022, 05:50:52 AM »
I don't understand how volt/m=C

Assuming from the context you mean V - volt (electric potential), m - meter (distance unit), C - coulomb (charge unit) - it is not, so whole discussion is a moot.

$$V = \frac {potential~~energy}{charge} = \frac J C = \frac {kg\times m^2}{C\times s^2} = \frac {kg\times m^2}{A\times s^3}$$

V/m is an electric field unit.

Integrating the electric flux over a closed surface will yield electric charge inside the surface (Gauss law), so these are all closely related units and and ideas, but they don't produce the relationship you stated.
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#### mjc123

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• Mole Snacks: +295/-12 ##### Re: Why in the equation E=v/d E units are coulomb
« Reply #3 on: October 28, 2022, 03:06:53 PM »
Are you confusing E (electric field strength, in V/m) with e (elementary charge, in C)?