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Finding required volume

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NotSoBrightGuy:
If I have a solution that follows:

22 Liters Non-Concentrated
18.5 Liters concentrated
= 1.2x Concentration factor

And I am required to put 1.4 Liters of Non-Concentrated volume between 13 other containers, How much volume of concentrated volume goes into each container?

Borek:
Please read the forum rules. You have to show your attempts at answering the question/solving the problem to receive help, it is a forum policy.

NotSoBrightGuy:
My apologies.

I assume that I have to take the 1.42 per container and divide that by the concentration factor of 1.2

= 1.42/1.2
= 1.18


Which equals to 1.18x13= 15.38 total liters
Am I on track here?

Borek:
What you wrote is highly ambiguous. If I am _guessing_ right what you are doing, you are correct.

Do I understand correctly that the procedure to follow is to add enough water to 18.5 L of the concentrated to dilute it to 22L?

And that the question is: how much of the concentrated solution needs to be put into 1.4 L (1.42 L?)container so that after filling it up with water the final concentration is the same as in the first case?

If so, yes, 1.18 L seems to be about OK (give or take some rounding errors, probably negligible).

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