What you wrote is highly ambiguous. If I am _guessing_ right what you are doing, you are correct.
Do I understand correctly that the procedure to follow is to add enough water to 18.5 L of the concentrated to dilute it to 22L?
And that the question is: how much of the concentrated solution needs to be put into 1.4 L (1.42 L?)container so that after filling it up with water the final concentration is the same as in the first case?
If so, yes, 1.18 L seems to be about OK (give or take some rounding errors, probably negligible).