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NaH dispersed in mineral oil (200%)
Malignoalfa:
synthesizing something I came across the following instruction:
"In a flask at room temperature (20-35 ° C.), 14.1 g (352 mmol) of NaH dispersed in mineral oil (200%) and 200 ml of DMSO were added."
I didn't understand this part:
"NaH dispersed in mineral oil (200%)"
would someone be kind enough to clarify for me?
thanks
Hunter2:
Its a special refined oil.
https://www.google.com/search?client=firefox-b-m&q=mineral+oil+200%25&oq=mineral+oil+200%25&aqs=heirloom-srp..0l3
Babcock_Hall:
https://pubs.acs.org/doi/10.1021/ba-1957-0019.ch011
I can only give you a partial answer. NaH is sold in several forms, including as a dispersion in mineral oil that is 60% NaH by mass (it is safer to handle than dry NaH). I have only used it one time. When I did, I weighed out the appropriate mass and rinsed with pentane or petroleum ether to remove the oil, then I used it immediately. One has to adjust the mass weighed out based on the portion that is mineral oil. I do not understand the meaning of 200%.
EDT
I am concerned that NaH and DMSO together might constitute a hazard (see link below). Perhaps there is a different protocol that you could use.
https://pubs.acs.org/doi/10.1021/acs.oprd.9b00276
Malignoalfa:
Thanks for the reply. I'm sure mineral oil is just a safety product for NaH to stop being explosive. That is, it doesn't matter the amount of oil in the reaction, just add the correct mole amount of NaH. I think the 200% refers to 2 parts NaH to one part Oil.
Thanks.
phth:
--- Quote from: Malignoalfa on January 31, 2023, 10:50:26 AM ---Thanks for the reply. I'm sure mineral oil is just a safety product for NaH to stop being explosive. That is, it doesn't matter the amount of oil in the reaction, just add the correct mole amount of NaH. I think the 200% refers to 2 parts NaH to one part Oil.
Thanks.
--- End quote ---
Could it be 20% dispersion in oil TYPO???? Why not just titrate the base following an established procedure if the protocol does not work???
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