4.5 g of aluminum is mixed with sulfur. How many grams of aluminum sulfide were obtained?
4,5g x mol, x g
2mol 3mol 1mol
x=0,17mol*1mol / 2 mol= 0,085mol
The answer of this task is 24,9 g Al2S3. Where am I wrong? I can solve other tasks using the same method, but this time I've got the wrong answer.