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Topic: Chemical Kinetics/Gibbs Free Energy  (Read 491 times)

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Offline rayyyu

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Chemical Kinetics/Gibbs Free Energy
« on: December 06, 2023, 04:23:07 PM »
Calculate ΔG (in kJ/mol) for this reaction if the temperature is instantaneously raised to
400.0 C at which Keq = 1.64 × 10–4. Assume that the reaction quotient (Q) is equal to the
value for the equilibrium constant you calculated in part a. Interpret your ΔG value.
Standard Delta G value is -32.8 kJ/mol
Answer for part A was 5.58 * 10^5
I tried using the formula ΔG = Standard ΔG + RTlnQ but I am getting answer of about 41 using the given values. I assume something has to be done with the 1.64 * 10^-4 value but I cannot seem to figure it out.

Offline Corribus

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Re: Chemical Kinetics/Gibbs Free Energy
« Reply #1 on: December 07, 2023, 10:20:55 AM »
Showing your work would help to diagnose your error. Only seeing half the problem also makes it difficult.
What men are poets who can speak of Jupiter if he were like a man, but if he is an immense spinning sphere of methane and ammonia must be silent?  - Richard P. Feynman

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