February 21, 2024, 12:26:33 PM
Forum Rules: Read This Before Posting

### Topic: Help needed with limiting reagents  (Read 307 times)

0 Members and 1 Guest are viewing this topic.

#### eastsherbert8948

• New Member
• Posts: 5
• Mole Snacks: +0/-0
##### Help needed with limiting reagents
« on: January 21, 2024, 07:51:06 PM »
What mass (g) of Na2CO3 would be needed to react with 0.250 mole HCl according to the equation:

Na2CO3 + 2 HCl → 2 NaCl + CO2 + H2O

(I got 13.25 grams of Na2CO3 would be needed to react with 0.250 moles HCl by multiplying 0.25 and 105.99g (molar mass of Na2CO3) - not sure if this is correct
« Last Edit: January 21, 2024, 10:39:55 PM by eastsherbert8948 »

#### Hunter2

• Sr. Member
• Posts: 2110
• Mole Snacks: +159/-47
• Gender:
• Vena Lausa moris pax drux bis totis
##### Re: Help needed with limiting reagents
« Reply #1 on: January 22, 2024, 01:31:43 AM »
Its wrong. You dont consider the ratio Carbonate and hydrochloric.

#### Borek

• Mr. pH
• Deity Member
• Posts: 27597
• Mole Snacks: +1794/-410
• Gender:
• I am known to be occasionally wrong.
##### Re: Help needed with limiting reagents
« Reply #2 on: January 22, 2024, 03:16:56 AM »
(I got 13.25 grams of Na2CO3 would be needed to react with 0.250 moles HCl by multiplying 0.25 and 105.99g (molar mass of Na2CO3) - not sure if this is correct

Here, and in other problems, you are just juggling numbers and you don't even pay attention to what you are doing. In most cases you start right, but you ignore the stoichiometric coefficient in the final step.

0.25 times 105.99 is not 13.25

Accidentally, the answer you gave (13.25 g of Na2CO3) is correct, even if it doesn't follow your calculations.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info