October 09, 2024, 10:04:28 AM
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Topic: Nitrobenzene reduction using Tin and Hydrochloric Acid mechanism  (Read 900 times)

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Offline auto4590

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Nitrobenzene reduction using Tin and Hydrochloric Acid mechanism
« on: September 07, 2024, 01:54:55 AM »
I found this, but my instructor said it is incorrect https://images.app.no_way/F53K5LMSaULxotky6. My instructor also said that Sn never forms a bond with N and it is a SET mechanism. I also found this https://onlinelibrary.wiley.com/cms/asset/443ca8bf-f886-4168-a0fb-84a53cedfc2a/poc3543-fig-0008-m.jpg, but it doesn't help me with the mechanism. I came up with a mechanism, but I don't feel confident about it at all. Does anyone know where I can find the correct mechanism? Or at least do you know if the reaction ratio between Sn:nitrobenzene is 3:1?

Offline Borek

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Re: Nitrobenzene reduction using Tin and Hydrochloric Acid mechanism
« Reply #1 on: September 07, 2024, 02:54:36 AM »
Your image doesn't show, what you posted is not a correct link.

My bet is that Sn itself doesn't matter much, it just reacts with the acid to produce hydrogen, the reducing agent. I can be wrong though, heavier metals often react to create complexes in which ligands have properties modified enough to facilitate some reactions.
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