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Topic: [Help]Balancing redox equations  (Read 50720 times)

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Demotivator

  • Guest
Re:[Help]Balancing redox equations
« Reply #15 on: October 19, 2004, 06:35:01 PM »
I think in this  case it's possible because the OH- that is added as base  just happens to be consumed by Fe3+ to form Fe(OH)3.

777888

  • Guest
Re:[Help]Balancing redox equations
« Reply #16 on: November 01, 2004, 10:51:42 AM »
How about this one? How can I balance it?

O3 + I-  ->  IO3(-) +O2  (acidic condition)

Skeleton half reactions:
3H2O + I-  ->  IO3(-) +6e + 6H(+)
O3 +I(-)  ->  IO3(-) ??? How can I write this skeleton half reaction? I don't know how to do :(

Please teach me! Thank you!

Demotivator

  • Guest
Re:[Help]Balancing redox equations
« Reply #17 on: November 01, 2004, 11:21:04 AM »
It is useful to recognize how to use H+ to produce H2O and the other product.

2e + 2H+  + O3 ->  H2O + O2
« Last Edit: November 01, 2004, 03:48:40 PM by Demotivator »

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