October 07, 2022, 02:14:29 AM
Forum Rules: Read This Before Posting

### Topic: Concentation problem  (Read 6735 times)

0 Members and 1 Guest are viewing this topic.

#### sbristow47

• Guest ##### Concentation problem
« on: April 04, 2004, 02:38:54 PM »
If you need to the determine the concentration of substance in a standard solution, and you know the molarity of a substance and the volume that you put in, do you use that initial molarity with the intial volume or do you have to detemine the molarity using the total overall volume of the solution?

#### jdurg

• Banninator
• Retired Staff
• Sr. Member
• • Posts: 1366
• Mole Snacks: +106/-23
• Gender: • I am NOT a freak. ##### Re:Concentation problem
« Reply #1 on: April 04, 2004, 03:09:45 PM »
Molarity is defined as the number of moles per total liter of solution.  So if you have a one molar solution, it is one mole of solute per liter of solution.  So in regards to your question, you'd have to use both.  First you'd determine the number of moles of solute you used based upon the molarity of the initial solution.  Once you had determined the number of moles of solute, you'd then divide it by the total amount of solution to get your concentration.

As an example, supposed you had 436 mL of a 2.0 molar solution of CuCl2 and you added that to 1000 mL of water.  Your first step would be determining how many moles of CuCl2 you have in your original solution.  Since one liter has 2.0 moles, .436 liters would have 0.872 moles.  With the number of total moles in your solution now known, you simply divide by the total number of liters of solution (1.436) and you'll have your solution's concentration; 0.607 Molar.

Make sense?
"A real fart is beefy, has a density greater than or equal to the air surrounding it, consists

#### sbristow47

• Guest ##### Re:Concentation problem
« Reply #2 on: April 04, 2004, 03:11:39 PM »
That's what I thought, but I just wanted to be sure. Thanks!