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Topic: Limiting Reactants  (Read 5888 times)

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Offline bppolivick

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Limiting Reactants
« on: February 09, 2007, 07:21:33 PM »
I'm working on this problem for my CHEM 111 class and I cannot seem to figure out this equation. 

CO (g) + 2H2 (g)  yields CH3OH (l)

If 11.92 grams of CO are mixed with 14.48 g H2 what is the theoretical yield (in grams) of CH3OH produced by the reaction?  In order for me to move on I need to know what is the amount of the product CH3OH in moles that can form?

moles CO = 0.4256 mol

Any help getting this figured out would be greatly appreciated.  Thanks.
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Offline Borek

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Re: Limiting Reactants
« Reply #1 on: February 09, 2007, 07:53:43 PM »
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Offline bppolivick

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Re: Limiting Reactants
« Reply #2 on: February 09, 2007, 08:01:06 PM »
Can I get any help with this specific problem?  Thanks.
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Offline chiralic

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Re: Limiting Reactants
« Reply #3 on: February 10, 2007, 02:07:37 AM »
Read these links: LINK 1, and LINK 2  there you'll get information and ideas about HOW TO SOLVE your"specific problem"


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Offline Mitch

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Re: Limiting Reactants
« Reply #4 on: February 10, 2007, 01:43:04 PM »
You need to balance it, before you can start approaching it!
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Offline enahs

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Re: Limiting Reactants
« Reply #5 on: February 10, 2007, 04:59:36 PM »
It is balanced, guys. That is carbon monoxide, not dioxide.
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Offline constant thinker

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Re: Limiting Reactants
« Reply #6 on: February 11, 2007, 10:29:41 PM »
Enahs is right, the equation is balanced.

You converted CO to moles. Now convert to H2 to moles, and figure out which reactant is limiting. Once you know the limiting reactant, find out how much CH3OH you can make with the amount of the limiting reactant that you have. Then you will have your theoretical yield.
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Offline kitfat2001

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Re: Limiting Reactants
« Reply #7 on: February 24, 2007, 09:27:47 AM »
ok, maybe i can help you~
From the equation, 1 mol CO will react with 2 mol H2
so 0.426 mol CO will react with 2x0.426(0.852) mole H2
however, there are 14.48 g H2which means there are 14.48/(1+1)=7.24mol H2
so H2 is in excess.
so the mol number of the product is equal to the mol number of CO because all CO can react with H2 completely
so the answer is equal 0.426 mol


**P.S.  If i get something wrong, please notice me. THANKS ;)
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