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Topic: Specific heat  (Read 4043 times)

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Specific heat
« on: October 24, 2004, 03:21:19 PM »
PLZ help me.
If 13.34 g of an unknown substance loses 40.8 J of heat in cooling from 50.0 degrees Celsius to 43.0 degrees Celsius, what is the specific heat of the unknown?
Plz explain to me how to find the answer

Offline Donaldson Tan

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Re:Specific heat
« Reply #1 on: October 26, 2004, 02:51:44 PM »
specific heat refers to specific heat capacity, ie. the amount of heat needed to raise the temperature of a unit amount of subtance by one unit temperature. Its SI unit is J.Kg-1K-1

Using Q = mc(dT) where
Q: heat applied
m: mass of substance
c: specific heat capacity
dT: change in temperature

-40.8J = (13.34 x 10-3 kg) X c X (43 - 50 K)

rearrange the above equation to solve..

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