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### Topic: Specific heat  (Read 5062 times)

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#### drummerchic00

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##### Specific heat
« on: October 24, 2004, 03:21:19 PM »
PLZ help me.
If 13.34 g of an unknown substance loses 40.8 J of heat in cooling from 50.0 degrees Celsius to 43.0 degrees Celsius, what is the specific heat of the unknown?
Plz explain to me how to find the answer

#### Donaldson Tan

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##### Re:Specific heat
« Reply #1 on: October 26, 2004, 02:51:44 PM »
specific heat refers to specific heat capacity, ie. the amount of heat needed to raise the temperature of a unit amount of subtance by one unit temperature. Its SI unit is J.Kg-1K-1

Using Q = mc(dT) where
Q: heat applied
m: mass of substance
c: specific heat capacity
dT: change in temperature

-40.8J = (13.34 x 10-3 kg) X c X (43 - 50 K)

rearrange the above equation to solve..

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