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Specific heat

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**drummerchic00**:

PLZ help me.

If 13.34 g of an unknown substance loses 40.8 J of heat in cooling from 50.0 degrees Celsius to 43.0 degrees Celsius, what is the specific heat of the unknown?

Plz explain to me how to find the answer

**Donaldson Tan**:

specific heat refers to specific heat capacity, ie. the amount of heat needed to raise the temperature of a unit amount of subtance by one unit temperature. Its SI unit is J.Kg-1K-1

Using Q = mc(dT) where

Q: heat applied

m: mass of substance

c: specific heat capacity

dT: change in temperature

-40.8J = (13.34 x 10-3 kg) X c X (43 - 50 K)

rearrange the above equation to solve..

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