I am having trouble with the simplicity of calculating molarity for a titration. Here is what I am given:

25.49 mL of NaOH were required to neutralize 0.5208g of KHP (M.W.=204.33) dissolved in water. this served to standardize NaOH

The vinegar solution for titration was prepared in the following manner: 25.0 mL of vinegar were diluted to 250.0 nL in a volumetric flash, and 25.0 mL of this diluted solution required 22.62 mL of the above standardized NaOH to reach phenolphthalein endpoint.

what was the molarity of the NaOH solution

what is the percentage by mass of the acid in the original vinegar sample.

- So I just get really stuck on all the equation stuff. I understand the concept fine, I just don't know how to apply it to the calculation. If you could help me with some steps to take that would be great. Thanks.