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Topic: Maximum cell potential calaulation  (Read 4278 times)

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777888

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Maximum cell potential calaulation
« on: October 28, 2004, 03:29:05 PM »
I have a question again!

Question: Make a galvanic cell that produces maximum voltage. Materials are chlorine gas, sodium chloride solution, nickel metal, nickel chloride solution,  platinum, and potassium nitrate solution.

Solution:(?)
I use the salt bridge method.
I use platimum in a solution NaCl(Na+,Cl- ions) with Cl2(g) inserted into the solution as the cathode AND I use nickel in a solution of nickel chlorine(Ni(2+),Cl-ions) as the anode. K+ ions in the saltbridge move to the cathode, and NO3(-) ions move to the anode.

I compared reduction potentials for Cl2(oxidizing agent) and Ni(reducing agent) and I found the cell potential = 1.64V

I am just wondering would this be the maximum voltage? Is this the highest voltage possible using the materials given?
« Last Edit: October 28, 2004, 03:32:00 PM by 777888 »

777888

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Re:Maximum cell potential calaulation
« Reply #1 on: October 29, 2004, 04:00:48 PM »
Will this be the highest voltage possible in the materials given?

Offline Donaldson Tan

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Re:Maximum cell potential calaulation
« Reply #2 on: October 29, 2004, 09:09:24 PM »
search the internet for nerst's equation.. it should provide you with a hint on how concentration affects the redox potential
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