Hey everyone.
I'm glad I found this forum, because I'm pretty stumped by this problem. I've been working on this for a long time now, and right now, I just really need your help.
Here goes.
A sample of diprotic acid with a mass of 0.1208 g is titrated with 0.1011 M NaOH, requiring 17.95 mL to reach the end point. Determine the formula mass of this acid.I'll denote the mystery diprotic acid with
H2A.
Ok, this is the only thing I know. In order to get the 0.1011 M NaOH, the equation must've looked like this, with the missing values in red:
0.1208 g H
2A x
moles H2A x moles NaOH x
1 = 0.1011M
grams H2A moles H2A 0.01795 L
And so.. I'm stuck.
Please help.
Thanks so much, I appreciate your time.