Topic: Very hard charge to mass ratio problem (Read 3826 times)

gmac525 · « **on:** November 12, 2006, 01:12:03 AM »

I can not figure this out.

The dipositve cation X²⁺ has e/m (charge to mass ratio) = 4.82 x 10³ C/g. Find the relative atomic mass of X.

A)87.7 B) 40.0 C) 65.6 D)137 E) 112

Help would be greatly appreciated. Thanks.

Borek · « **Reply #1 on:** November 12, 2006, 06:04:33 AM »

Solve for m. Then you will need conversion factors, which you can get from dimensional analysis.

gmac525 · « **Reply #2 on:** November 12, 2006, 11:35:28 AM »

I still do not know how to do this. All I have is information which I do not know how to use. Am I going in the right direction?

1.602x10^-19C x 2 = 3.204 x 10 ^-19

3.204 x 10 ^-19 x 6.022 x 10²³ atoms = 192,944.88 C/ mol
atom 1 mol

192,944.88 C / 4.82 x 10³ = 40.0 ??

Borek · « **Reply #3 on:** November 12, 2006, 02:07:03 PM »

Quote from: gmac525 on November 12, 2006, 11:35:28 AM

192,944.88 C / 4.82 x 10³ = 40.0 ??

OK

gmac525 · « **Reply #4 on:** November 12, 2006, 04:25:22 PM »

Thank you, that helped me a lot. Here, have some scooby snacks

Topic: Very hard charge to mass ratio problem (Read 3826 times)

gmac525

Very hard charge to mass ratio problem

Borek

Re: Very hard charge to mass ratio problem

gmac525

Re: Very hard charge to mass ratio problem

Borek

Re: Very hard charge to mass ratio problem

gmac525

Re: Very hard charge to mass ratio problem

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