April 19, 2024, 06:11:01 PM
Forum Rules: Read This Before Posting


Topic: atomic physics; KE and TE  (Read 3862 times)

0 Members and 1 Guest are viewing this topic.

Offline xstrae

  • Full Member
  • ****
  • Posts: 131
  • Mole Snacks: +5/-5
  • Gender: Male
  • Life rocks!
atomic physics; KE and TE
« on: November 14, 2006, 02:12:36 PM »
How much will the kinetic energy and total energy of an electron in H atom change if the atom emits a photon of wavelength 4860Ao?

[Solution : KE increases by 2.553 eV and TE decreases by 2.553eV]

I used E = hc/? and calculated the energy lost in emitting a photon. It came out to be 2.533eV
Total energy of ground state H atom = -13.6eV

so total energy increases by 2.553eV.
is this correct? and how do I calculate the change in kinetic energy?

thanks for your time.

Sponsored Links