Can anyone tell me if this is right?

AuCl_{3(aq)} + Cd_{(s)} > Au_{(s)} + CdCl_{2(aq)}

I got to the step with the ratio question

There should be 3 Cd atoms when there are 2 Au atoms

So,

2AuCl_{3(aq)} + 3Cd_{(s)} > Au_{(s)} + CdCl_{2(aq)}

2AuCl_{3(aq)} + 3Cd_{(s)} > 2Au_{(s)} + 3CdCl_{2(aq)}

Is that all right?

Also, the ratio thing was sort of confusing.

I found that the difference in electrons for Au was 3, and the diff for Cd was 2, so then do I reverse the numbers and then it should be that there must be 3 Cd atoms for every 2 Au atoms?

Confusing:/