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Topic: Spectator ions (URGENT)  (Read 17885 times)

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Offline Borek

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Re: Spectator ions (URGENT)
« Reply #15 on: November 23, 2006, 06:56:55 PM »
No such thing as O- ions, you probably mean OH-. They are of no use here.

Are the ions created H(+) Cl(-) and Ca(2+) Cl(-)???

Yes. Finally we are moving ahead ;)

Now, ALL you have to do is to rewrite the original reaction (the one you have posted in your very first letter) putting these dissociated substances into it. Don't touch CaCO3, nor CO2 nor water.
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Offline unkwown

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Re: Spectator ions (URGENT)
« Reply #16 on: November 24, 2006, 04:56:49 PM »
Can i just clarify is calcuim an ion? Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons.

I can only get my equation down to
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-)

From my orginal question, which ions are the spectator ions?

Offline Albert

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Re: Spectator ions (URGENT)
« Reply #17 on: November 24, 2006, 05:16:31 PM »
Don't touch CaCO3, nor CO2 nor water.

What's left among the products?  ;)

Offline Borek

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Re: Spectator ions (URGENT)
« Reply #18 on: November 24, 2006, 07:58:01 PM »
Can i just clarify is calcuim an ion? Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons.

I can only get my equation down to
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-)

From my orginal question, which ions are the spectator ions?

Calcium in calcium carbonate is already in ionic form - but, as the salt is insoluble, you don't write it as ion.

In the final equation please don't use form Ca(2+)Cl2(-) as it is probably source of the part of the confusion. What you have is Ca2+ + 2 Cl-.
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Offline Borek

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Re: Spectator ions (URGENT)
« Reply #19 on: November 24, 2006, 07:59:58 PM »
Don't touch CaCO3, nor CO2 nor water.

What's left among the products?  ;)

I am afraid you are not helping, but just adding to the unkwown confusion. His original equation listed all correct products, not necesarilly in the ionic form. But H2O and CO2 were OK.
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Offline unkwown

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Re: Spectator ions (URGENT)
« Reply #20 on: November 25, 2006, 10:28:42 AM »
can we start again  :-\

I have the equation:

CaCO3                 + 2HCl                  -->   CaCl2                + H20
Calcuim Carbonate + Hydrochloric Acid -->   Calcuim Chloride + Water

which goes to:
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-) + H2O

is this correct so far?

Can i asK:

Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons yet??

Thankyou

Offline Alberto_Kravina

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Re: Spectator ions (URGENT)
« Reply #21 on: November 25, 2006, 10:32:38 AM »
Quote
Calcuim is an element right wanting to lose 2 electrons to make outershell complete. Why do i write it as an ion, with the 2+ above it? It hasn't lost any electrons yet??
Calcium tends to lose 2 electrons, yeah, but in the carbonate it has already lost it's valence electrons, so it is impossible for the charged ion to lose other 2 electrons!

Offline tbuihuu

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Re: Spectator ions (URGENT)
« Reply #22 on: November 26, 2006, 06:56:59 AM »
Quote
CaCO3                 + 2HCl                  -->   CaCl2                + H20
Calcuim Carbonate + Hydrochloric Acid -->   Calcuim Chloride + Water

which goes to:
Ca(2+)CO3(2-) -> Ca (2+)Cl2 (-) + H2O
it isn't correct. Only strongly dissociation substance may be change to ionic. so you can't write CaCO3 to Ca2+CO32-.And that reaction can be write:
CaCO3   +  2H+  ---> Ca2+  +  CO2  +  H2O

Offline unkwown

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Re: Spectator ions (URGENT)
« Reply #23 on: November 27, 2006, 04:01:55 PM »
When you talk about a dissociation substance, do you mean a compound that has been bonded ionoically? Ive never heard of the term dissociation (maybe it's a amercianism?)

Offline Alberto_Kravina

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Offline unkwown

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Re: Spectator ions (URGENT)
« Reply #25 on: November 28, 2006, 04:35:03 PM »
cheerz. Another question:

a isotope is define: Nuclei containing the same number of protons but different numbers of neutrons. Most elements can exist in several isotopic forms. A common example of an isotope is deuterium, which differs from normal hydrogen by the presence of an extra neutron in the nucleus.


but in the perodic table loads of element have a different number of neutrons to protons:

 Al has 14 protons and 13 neutrons, does this make it an isotope.

isn't hydrogen a isotope

But i've search and hydrogen isn't a isotope, the first one is deuterium

are about half the elements isotopes then?

Offline Borek

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Re: Spectator ions (URGENT)
« Reply #26 on: November 28, 2006, 05:15:12 PM »
Don't post different question in an old thread, start new one whe the question is new.

Every atom is an isotope.

Hydrogen has three isotopes - hydrogen (sometimes called protium), deuterium and tritium. In fact there are much more hydrogen isotopes, but these three are most important.
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Offline Dan

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Re: Spectator ions (URGENT)
« Reply #27 on: November 28, 2006, 05:37:23 PM »
a isotope is define: Nuclei containing the same number of protons but different numbers of neutrons.

..

but in the perodic table loads of element have a different number of neutrons to protons:

You have misunderstood the definition.

The tree most important isotopes of H, as Borek has already said, are protium, deuterium and tritium

Protium ("normal" hydrogen): 1 proton, 0 neutrons
Deuterium: 1 proton, 1 neutron
Tritium: 1 proton, 2 neutrons.

Now, all three have the same number of protons in the nucleus (1) but the number of neutrons vary, so protium, deuterium and tritium are said to be isotopes of hydrogen.

In the same way, 35Cl and 37Cl (the superscript number is the atomic mass) are isotopes of Cl. Both have 17 protons, but the number of neutrons differ. These are the main isotopes of Cl, and exist in a 3:1 ratio of 35Cl to 37Cl (approximately), which is why the atomic mass of Cl is quoted on periodic tables as about 35.5.
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