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Topic: Cadmium (II) Polarography  (Read 3559 times)

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Offline tiger1987

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Cadmium (II) Polarography
« on: November 25, 2006, 02:11:29 AM »
I am doing a cadium (II) polarography experiment, and when I calculate the value of n for my polarograms, I get 1 e-. I should be getting 2 e- because the oxidation state of cadmium is +2. What could possibly be causing this problably? ( I have double and triple checked my values for n and it still comes out to 1 e-.
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Online Borek

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Re: Cadmium (II) Polarography
« Reply #1 on: November 25, 2006, 05:08:53 AM »
Not enough info IMHO. Post some details.
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Offline chiralic

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Re: Cadmium (II) Polarography
« Reply #2 on: November 25, 2006, 07:41:25 PM »
Hi Tiger1987:

I recommend you read chapter 22 of book Problems and Experiments in Instrumental Analysis by Meloan-Kiser (I have it version in spanish), there you can find EXACTLY what are you looking for...

You must plot Log(I/Id-I) vs E, you'll get a "lineal" curve where the slop value is equal to n/0.0591.
Then you'll get a "n"

Inside of this book you can find an exercise from experimental data and they got n=1.75 for Cd+2
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