March 28, 2024, 05:14:58 PM
Forum Rules: Read This Before Posting


Topic: Question about Solubility Products  (Read 12234 times)

0 Members and 1 Guest are viewing this topic.

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27633
  • Mole Snacks: +1799/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Question about Solubility Products
« Reply #15 on: December 06, 2006, 07:06:57 PM »
It is all in solution stoichiometry - imagine 1 mol of CaSO4 was dissolved in some volume of water. How many moles of Ca2+ and how many moles of SO42- are present in the solution?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Jinn21

  • New Member
  • **
  • Posts: 8
  • Mole Snacks: +0/-0
Re: Question about Solubility Products
« Reply #16 on: December 06, 2006, 07:35:06 PM »
Well, the Molar mass of  CaSO4 is 136g
Ca has a mass of 40g
and SO4 has 96g

So: Ca- 40g/136g = 0.29 mols -->0.30 mols
SO4- 96g/136g = 0.70 mols

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27633
  • Mole Snacks: +1799/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Question about Solubility Products
« Reply #17 on: December 06, 2006, 07:58:44 PM »
No. Look at the reaction equation. And read second paragraph on this page:

http://www.chembuddy.com/?left=balancing-stoichiometry&right=stoichiometric-calculations
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links