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Topic: calorimetry and specific heat  (Read 4090 times)

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dexangeles

  • Guest
calorimetry and specific heat
« on: November 22, 2004, 03:08:48 AM »
you're trying to determine the specific heat of an object through calorimetry
obviously there's going to be water in the container
if the container has a high specific heat vs low specific heat, how does it affect the value of the object's specific heat when calculated, would it increase or decrease it?

higher specific heat of container = higher object c obtained or lower c obtained


Demotivator

  • Guest
Re:calorimetry and specific heat
« Reply #1 on: November 22, 2004, 10:54:53 AM »
The object's specific heat is independent of the container's.

q = qobj + qcal + qw = 0   q is heat, net change is zero.
where qobj < 0, because the hot object will lose heat to the calorimeter and water.

qobj = mobj x Cobj ( Tf - Tobj )
qcal = Ccal ( Tf - Ti )
qw = mw x Cw ( Tf - Ti )
 

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