[Dolphinsiu]

You are provided with (i) theoretic bond refractive index (Table 1), (ii) density, p (1.046 gcm-3) and molecular weight, ( M=60) of acetic acid(ethanoic acid) and (iii) equation (1), Estimate the refractivve index, n of acetic acid.

           Table 1

             Bond refractive index
C-H                  1.65
C-C                  1.20
C=O                3.34
C-O                 1.41
O-H                 1.85

Mr = ( M /p) x (n^2 -1) / (n^2 + 2)..(1)

I have found the theoretic bond refractive index of acetic acid
= 3 x 1.65 + 1.20 + 3.34 + 1.41 + 1.85 = 12.75

But what is the use of the two datas and equation(1)? Also, I don't know what Mr is.
So I cannot know how to estimate refractive index of acetic acid. Please *delete me*

[chiralic]

Also, I don't know what Mr is.

Mr is: MOLAR REFRACTION

[Dolphinsiu]

You are very clever! Thank you!

[chiralic]

Typing in google the keyword that I wrote in my last post in this subject you'll get A LOT information about you Question and How to interpreting the Lorentz-Lorenz equation

Have a nice day

Chiralic

[Dolphinsiu]

Yes! I have done it.
n is equal to 1.36. isn't it?

[chiralic]

Right!  You are very clever too!

Have a nice day

Chiralic