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Topic: Making Nylon 6.6  (Read 6611 times)

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Offline iyc

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Making Nylon 6.6
« on: November 25, 2004, 05:58:53 AM »
In manufacturing Nyon 6.6, a solution of hexane-1,6-diamine(in NaOH(aq)) is added to a solution of hexanedioyl dichloride (in 1,1,1-trichloromethane).

- What is the use of aqueous sodium hydroxide and 1,1,1-trichloromethane ???
- If replace the aqueous sodium hydroxide with 1,1,1-trichloromethane, what will happen ???
- If replace the aqueous sodium hydroxide with water, what will happen ???

Offline AWK

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Re:Making Nylon 6.6
« Reply #1 on: November 25, 2004, 08:31:46 AM »
Chloroform is just a solvent for organic compounds. You have water in solution of NaOH.
In classic Schotten-Baumann reaction other basic compounds can be used, eg: Na2CO3, CaO, BaO, MgO, NaHCO3 or CH3COONa.
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Offline iyc

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Re:Question about Making Nylon 6.6 reply
« Reply #2 on: November 25, 2004, 10:10:21 AM »
Excuse me. I would like to ask one more question.
Is it possible that NaOH(aq) is used to provide a alkaline medium to prevent the amine from dissociate( I don't know whether it is described as dissociate) resulting into no raw material for the reaction?

Offline AWK

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Re:Making Nylon 6.6
« Reply #3 on: November 26, 2004, 01:11:59 AM »
Any base in this reaction is used for removing of HCl. otherway you should use more amine (it is also basic) and amine hydrochloride is formed.
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Offline iyc

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Re:Making Nylon 6.6
« Reply #4 on: November 26, 2004, 07:15:36 AM »
But, what is the aim to remove the HCl molecules?

Offline Donaldson Tan

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Re:Making Nylon 6.6
« Reply #5 on: November 26, 2004, 10:20:51 AM »
nylon with traces of hydrochloric acid isn't safe to handle. it's corrosive.
"Say you're in a [chemical] plant and there's a snake on the floor. What are you going to do? Call a consultant? Get a meeting together to talk about which color is the snake? Employees should do one thing: walk over there and you step on the friggin� snake." - Jean-Pierre Garnier, CEO of Glaxosmithkline, June 2006

Offline movies

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Re:Making Nylon 6.6
« Reply #6 on: November 26, 2004, 03:23:28 PM »
As AWK alluded to, if you didn't use another base then you would need at least 2 equivalents of amine since the HCl formed in the reaction would protonate any free amine and make it unreactive in the polymerization reaction.

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