[yoly]

When sodium carbonate reacts with hydrochloric acid, the carbonic acid
that is formed immediately breaks down into carbon dioxide and water.  What
weight of sodium carconate would have been present originally if 5.0 L of carbon
dioxide were obtained in this way?

Na2CO3 + 2HCl -- 2NaCl +CO2 +H2O

My work is below:

5 L CO2  X 1 mol CO2/1 L CO2 X 1mol Na2CO3/1 mol CO2 X 105.99g Na2CO3/1mol Na2CO3 = 530g Na2CO3

[Yggdrasil]

1 mol CO2/1 L CO2

Are you sure that this conversion is correct?

[english]

I'm getting around 24.g, because I'm assuming STP with this problem.  So I assumed that 1 mol of CO₂ occcupied a volume of 22.41L.

With this I concluded that 5.0L of CO₂ at STP was (without rounding) .2231 mol of CO₂.


I do not know if this is a worthy assumption, giving the problem.