The solubility product of calcium hydroxide, Ca(OH)2, is 7.9 x 10-6 at 25ÂșC. Will a precipitate form when 100mL of 0.10 mol/L of CaCl2 solution and 50.0 mL of 0.70 mol/L of NaOH solution are combined? Show your work.

This is my work, but I dont know if I am even close-can someone check it to ensure I did it right?

[CaCl2] = 0.10 mol/L x 100 ml(0.1 L) = 0.066 mol/L

150 mL(0.15 L)

[NaOH] = 0.70 mol/L x 50 ml(0.05 L) = 0.233 mol/L

150 mL(0.15 L)

Ksp = [CaCl2] [NaOH] = 0.015 => 1.5 x 10 -2

Since Ca(OH)2 = 7.9 x 10-6 which is < 1.5 x 10 -2 then no precipitate will form.

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