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Topic: Some questions  (Read 4754 times)

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Offline AirForceOne

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Some questions
« on: January 11, 2007, 01:35:49 AM »
Hi, need some quick help.  No time to explain how I tried it, I am getting really frustrated with the amount of work I have (3 tests tomorrow), just need the quick answers

1)


2)


3)


Sorry and thank a lot!
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Offline Bakegaku

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Re: Some questions
« Reply #1 on: January 11, 2007, 09:21:32 AM »
Read the rules and regulations so we don't answer questions you could benefit from doing yourself, please.  Show your attempts at answering the question.

http://www.chemicalforums.com/index.php?page=forumrules

Some help I will offer you, though:

1) Which one(s) have/has complete shells or orbitals?  Are they more or less stable?

3) which is hardest to give a plus charge?
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Offline AWK

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Re: Some questions
« Reply #2 on: January 11, 2007, 10:55:21 AM »
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Offline vhpk

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Re: Some questions
« Reply #3 on: January 13, 2007, 12:53:22 AM »
Why does HNO3 has the oxidize with every concentration but H2SO4 only has that property when it is compact
Sorry if my English is bad ;D
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Offline vhpk

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Re: Some questions
« Reply #4 on: January 14, 2007, 10:35:29 PM »
We have some half-reactions:
NO3(aq)- + 2H+aq + e <--> NO2(g) + H2O(l)
NO3(aq)- + 10H+aq + 8e <--> NH4(aq)+ + 3H2O(l)
According to the reactions, we can guess that, with HNO3 in compact concentration there will be NH3 and with HNO3 in weak concentration there will be NO2 but the truth is not, why
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Offline Borek

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Re: Some questions
« Reply #5 on: January 15, 2007, 03:33:26 AM »
Where is the other half-reaction?
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Offline vhpk

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Re: Some questions
« Reply #6 on: January 15, 2007, 11:55:55 PM »
Quote from: Borek on January 15, 2007, 03:33:26 AM
Where is the other half-reaction?
Sorry, I don't mean half-reaction but I mean the reduction of reaction, but I don't have enough vocabulary to express my idea, so please accept, and this reaction:
Quote from: vhpk on January 14, 2007, 10:35:29 PM
NO3(aq)- + 2H+aq + e <--> NO2(g) + H2O(l)
Eo = 0,8V
Quote
NO3(aq)- + 10H+aq + 8e <--> NH4(aq)+ + 3H2O(l) Eo = 0,88V
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Offline Borek

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Re: Some questions
« Reply #7 on: January 16, 2007, 04:07:14 AM »
You need reductor for both reactions to proceed. So far you have listed only oxidation half reactions. As long as you don't add a reductor nothing will happen.
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Offline vhpk

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Re: Some questions
« Reply #8 on: January 16, 2007, 08:12:27 PM »
Al --> Al3+ + 3e
Sorry, ;D, I want to have a general view about every metal, so I didn't write it
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