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Topic: Single Displacement Rx - Verification  (Read 6474 times)

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Offline Atome

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Single Displacement Rx - Verification
« on: January 18, 2007, 10:24:22 PM »
Hello everyone,

   Could you please tell me if this single displacement reaction is true/works?

Fr + CsBr --> Cs + FrBr


I'd like to see if Francium can displace Caesium.

Thanks,

James

Offline Borek

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Re: Single Displacement Rx - Verification
« Reply #1 on: January 19, 2007, 11:47:52 AM »
Think activity series, think trends in periodic table.
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Offline Mitch

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Re: Single Displacement Rx - Verification
« Reply #2 on: January 20, 2007, 01:08:40 AM »
In aqueous media, the above reasoning isn't valid at all.
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Re: Single Displacement Rx - Verification
« Reply #3 on: January 20, 2007, 01:54:47 AM »
If Fr is higher then Cs on the activity theory, then in theory, it should work.

Offline vhpk

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Re: Single Displacement Rx - Verification
« Reply #4 on: January 20, 2007, 06:14:42 AM »
Perhaps the reason is that Fr is a radioactive element ;D
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Offline Atome

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Re: Single Displacement Rx - Verification
« Reply #5 on: January 22, 2007, 08:10:18 PM »
Thanks for your replies, I am saying that this reaction will work since Francium and Caesium both have a valence of +1.

Is my hypothesis correct?

Offline Dan

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Re: Single Displacement Rx - Verification
« Reply #6 on: January 22, 2007, 08:21:30 PM »
Your reasoning is not correct. Will Li + CsBr --> Cs + LiBr happen on the grounds that Li and Cs both have a valence of +1?
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Offline constant thinker

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Re: Single Displacement Rx - Verification
« Reply #7 on: January 22, 2007, 08:32:17 PM »
Mitch has a good point about the reaction in an aqueous media.

Perhaps the reason is that Fr is a radioactive element ;D

Also, just because it's radioactive, it doesn't mean it won't react. Uranium naturally exists in an oxide form, and it's radioactive. Other radioactive elements will react and form compounds also.
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Offline Atome

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Re: Single Displacement Rx - Verification
« Reply #8 on: January 22, 2007, 09:22:16 PM »
Thanks for your replies. I see what you mean, and I figured out a new single displacement reaction:

Li + CsI -> Cs + LiI   

I presume that this reaction would work since Lithium is higher than Caesium in the Activity Series, thus displacing the Caesium in Caesium Iodide.

Am I correct?

Thanks.

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Re: Single Displacement Rx - Verification
« Reply #9 on: January 23, 2007, 07:41:36 PM »
No, the example was to illustrate that just because the valence is +1 in both cases, doesn't mean the reaction happens. The reaction does not happen because Cs is (much) higher in the reactivity series than Li

Observe:

Li + water

Cs + water
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Offline vhpk

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Re: Single Displacement Rx - Verification
« Reply #10 on: January 23, 2007, 11:02:06 PM »
I  want to ask if there is this reaction:
F2 + AgNO3 --> FNO3 + AgF
If there is this reaction, I want to ask F doesn't have oxidation number +1, yeah, and you see in this reaction is that F has oxidation number +1
;D
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