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Topic: Atomic Composition Calculations  (Read 4583 times)

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Offline Megan

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Atomic Composition Calculations
« on: January 25, 2007, 01:33:02 PM »
Ok I have to figure out how many protons, neutrons, and electrons are in of the following: 116 B, 55 over 26 Fe

11/6 B = n6 e&p 5 each

55/26 Fe = n24 e&p 26 each

Is this right our did I miss read then info?
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Offline Borek

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Re: Atomic Composition Calculations
« Reply #1 on: January 25, 2007, 01:48:44 PM »
11/6 B? Strange question. Or tricky.

55-26 - how much is it?
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Offline Megan

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Re: Atomic Composition Calculations
« Reply #2 on: January 25, 2007, 01:51:52 PM »
11/5 B
55-26=29
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Offline Borek

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Re: Atomic Composition Calculations
« Reply #3 on: January 25, 2007, 04:03:43 PM »
Good. Your answer to the first question was OK. Check the second.
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Offline Megan

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Re: Atomic Composition Calculations
« Reply #4 on: January 25, 2007, 04:52:28 PM »
55/26Fe in not 29n e&p 26 each. Then I do not understand why this is wrong and the other one is right. I am having a very hard time in this class and their are no tutors
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Offline Dan

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Re: Atomic Composition Calculations
« Reply #5 on: January 25, 2007, 05:01:46 PM »
Quote from: Megan on January 25, 2007, 04:52:28 PM
55/26Fe in not 29n e&p 26 each. Then I do not understand why this is wrong and the other one is right. I am having a very hard time in this class and their are no tutors

29n, 26p&e is correct. Your original answer (24n, 26p&e) was wrong, do you see why?
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Offline Megan

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Re: Atomic Composition Calculations
« Reply #6 on: January 25, 2007, 05:19:29 PM »
Yeah I do. My math was off. Thank you for your help.
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