I am analysing biomass material using HPLC and I have totally confused my self over dilution. I have an answer to the following but would love someone else to confirm it. And maybe show working out.
I had a 0.01g sample of pure material (compound X) which I diluted in 1 ml of water from this solution I took 0.1 ML of liquid and diluted it in 1 ML of water. This gave me a 1 mg in 1 ML standard (well almost) which I used to calibrate the Machine; the machine gave an integration of 52500 for 1 mg in 1 ML.
For my unknown sample I macerated 60g in 90 ML water, from this solution I took 0.1ML and diluted this with 1 ML of water. The machine gave this a value of 2656.
So my question what % of my unknown sample is compound X?