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Topic: can i get help with some buffer questions, please  (Read 4241 times)

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Offline newuser

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can i get help with some buffer questions, please
« on: February 18, 2007, 11:43:16 AM »
1. How many mL of 2.0 M HCl must be added to 1.00 L of a 0.100 M solution of sodium formate to produce a buffer with pH 4.00? (Ka formic acid = 1.9 × 10?4)

2. A solution is made by adding 25.0 mL of a 0.123 M solution of the weak base CH3NH2 to 35.0 mL of
a 0.213 M solution of HCl. What is the resulting pH?

3. What is the pH of a solution made by mixing 500 mL of 1.00 M HCN and 1.50 L of 0.250 M NaOH, and then diluting the entire solution to 3.00 L? (Ka HCN = 4.0 × 10?10)

Offline Borek

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Re: can i get help with some buffer questions, please
« Reply #1 on: February 18, 2007, 12:07:03 PM »
Please read forum rules.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline newuser

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Re: can i get help with some buffer questions, please
« Reply #2 on: February 18, 2007, 12:20:45 PM »
Thank you for sending me the rules of this forum...they were helpful, but how can I get the help with these questions...Is there any specific link on this forum and can you give me a good example of a good title instead of my title that I have had for this topic? Thank you again for help   :)

Offline Borek

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Re: can i get help with some buffer questions, please
« Reply #3 on: February 18, 2007, 12:24:45 PM »
First of all - you have to try by yourself.

In case you have no idea where to start (your notes or course workbook are a good idea) visit pH calculation lectures. See the questions link in the left menu, there are some examples similar to questions you have posted.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline newuser

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Re: can i get help with some buffer questions, please
« Reply #4 on: February 18, 2007, 12:28:50 PM »
thank you  :)

Offline english

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Re: can i get help with some buffer questions, please
« Reply #5 on: February 18, 2007, 08:10:19 PM »

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