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Topic: Net Ionic Equations  (Read 13254 times)

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Tooren

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Net Ionic Equations
« on: December 06, 2004, 12:06:26 AM »
Just a short question:
Now the molecular equation between LiOH (aq) with HBr (aq) is (I presume):
LiOH (aq) + HBr (aq) ----> LiBr (aq) + H(2)O (l)
Now I'm confused about the net ionic, since there are no ions.
Would it just be:
OH(-) (aq) + H(+) (aq) ---> H(2)O (l)?

Offline jdurg

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Re:Net Ionic Equations
« Reply #1 on: December 06, 2004, 11:05:40 AM »
Just a short question:
Now the molecular equation between LiOH (aq) with HBr (aq) is (I presume):
LiOH (aq) + HBr (aq) ----> LiBr (aq) + H(2)O (l)
Now I'm confused about the net ionic, since there are no ions.
Would it just be:
OH(-) (aq) + H(+) (aq) ---> H(2)O (l)?

Yes, you are correct!   ;D  With the LiOH and HBr being in aqueous solution, they would both start out as Li+, OH-, H+, and Br-.  After the reaction, you'd wind up with LiBr in solution, but since they are in solution the ions would be present as Li+ and Br-.  Therefore, the overall ionic equation would include those ions, but the initial question was asking for the Net Ionic Equation.  In a Net Ionic Equation, you omit any ions which do not change.  Therefore, since the Li+ and Br- both began as ions, and ended up as ions, they are removed.  

So you have shown the correct answer.  Good job.   ;D
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