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Topic: Dissociation of H2S  (Read 19666 times)

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Offline mooreso

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Dissociation of H2S
« on: February 25, 2007, 11:42:11 AM »
Am taking an engineering design class after not having chemistry for 15 years.  I am having problems solving what appears to be a simple dissociation problem:

The pH of an acid mine drainage through which hydrogen sulfide bubbles continuously is measured and found to have a value of pH = 3.7.   Estimate the Concentration of S2- in this water.

Answer: 3 x 10-15 mol/L

Can anyone give me a hand so I can see the process for solving this? 

Offline Borek

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Re: Dissociation of H2S
« Reply #1 on: February 25, 2007, 01:08:51 PM »
Not enough data to calculate concentration.

You need to use second overall dissociation constant (see dissociation constants explained), but without information about H2S concentration you can't do anything.
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Offline mooreso

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Re: Dissociation of H2S
« Reply #2 on: February 25, 2007, 01:37:24 PM »
I taslked to the professor... he intimated that there is a solution and that somehow it involves assumptions pertaining to the initial concentration.  I agree with you, however, that without the initial concentration of H2S it would eem impossible.

Offline lemonoman

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Re: Dissociation of H2S
« Reply #3 on: February 25, 2007, 01:55:31 PM »
The pH of an acid mine drainage through which hydrogen sulfide bubbles continuously

without information about H2S concentration you can't do anything.

There is no initial concentration...the water is 'saturated' with H2S.

You need to use second overall dissociation constant

Definitely.  And the first overall dissociation constant.

This, and the Ksp of H2S (probably also available in the textbook where you find the dissociation constant) ... that is all one needs (in addition to what is given).

Offline Borek

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Re: Dissociation of H2S
« Reply #4 on: February 25, 2007, 03:49:25 PM »
without information about H2S concentration you can't do anything.

There is no initial concentration...the water is 'saturated' with H2S.

And that's information about concentration - the one that is needed - but it is still not quantitative, only qualitative.

Quote
You need to use second overall dissociation constant

Definitely.  And the first overall dissociation constant.

You can safely ignore first dissociation step.

http://www.chembuddy.com/?left=pH-calculation&right=pH-polyprotic-acid-base#eq9.13

See equation 9.13 - denominator in acidic solutions is for all practical purposes only pH dependent, with both dissociation constants being very low.

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This, and the Ksp of H2S (probably also available in the textbook where you find the dissociation constant) ... that is all one needs (in addition to what is given).

Ksp?
« Last Edit: February 25, 2007, 05:46:55 PM by Borek »
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Offline lemonoman

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Re: Dissociation of H2S
« Reply #5 on: February 25, 2007, 09:12:13 PM »
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Ksp?

Solubility product constant.

For A2B(s) <--> 2 A+(aq) + B-(aq)

Ksp = [A+(aq)]2[B-(aq)] / [AB(s)]
~~ [A+(aq)]2[B-(aq)]

since [AB(s)] ~ 1

where [] are activities, but can safely be approximated by the concentrations for dissolved substances.

Offline AWK

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Re: Dissociation of H2S
« Reply #6 on: February 26, 2007, 01:35:14 AM »
Am taking an engineering design class after not having chemistry for 15 years.  I am having problems solving what appears to be a simple dissociation problem:

The pH of an acid mine drainage through which hydrogen sulfide bubbles continuously is measured and found to have a value of pH = 3.7.   Estimate the Concentration of S2- in this water.

Answer: 3 x 10-15 mol/L

Can anyone give me a hand so I can see the process for solving this? 
The simple approximate solution of this problem (assuming only H2S is responsible for acidity) - [H+]=Ka2
AWK

Offline Borek

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Re: Dissociation of H2S
« Reply #7 on: February 26, 2007, 02:58:55 AM »
Quote
Ksp?

Solubility product constant.

What does it have to do with the pH of dissolved gas calculations?
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Offline Borek

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Re: Dissociation of H2S
« Reply #8 on: February 26, 2007, 03:02:56 AM »
The simple approximate solution of this problem (assuming only H2S is responsible for acidity) - [H+]=Ka2

What a shame :( I am explaining it on my own site...

http://www.chembuddy.com/?left=pH-calculation&right=pH-polyprotic-simplified#eq10.8
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Offline lemonoman

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Re: Dissociation of H2S
« Reply #9 on: February 26, 2007, 03:50:21 PM »
What does it have to do with the pH of dissolved gas calculations?

I made a small error, but I still think you're wondering about how pH ties into it:

For H2S:

H2S <--> 2 H+ + S2-

Ksp = [H+]2[S2-] / [H2S]
So [S2-] = (Ksp)[H2S] / [H+]2

where [H+] = 10-pH

My mistake was, the activity of H2S isn't 1 because (silly me) it's a gas.  And gases are more complicated because they dissolve in liquids AS a gas, rather than dissociating into ions.

So in conclusion, my way doesn't work.

Offline Borek

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Re: Dissociation of H2S
« Reply #10 on: February 26, 2007, 04:04:17 PM »
What you call Ksp is just an overall second dissociation constant.
« Last Edit: February 26, 2007, 04:27:24 PM by Borek »
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