Ok, I've been struggling with this question for a few hours now, and its given me a lot of trouble:
For the rxn CaCO3 (s)-> CaO (s) + CO2 (g) : Delta H rxn= +177.5 kj/mol, and delta S rxn = 162.7 J/K mol. Assuming that these quantities do not depend on temperature, calculate the equilibrium partial pressure of CO2 at 825.5 K when the rxn takes place in a closed container originally devoid of any excess CO2 gas. (4 sig figs)
Ok, I've been using the equations G=Delta H rxn - T*delta S rxn, then taking that value and plugging it into
Delta G rxn=-2.3 RT log K
I know the K expression is [CO2]
Now...the correct answer is 1.850 * 10 ^-3
Why and how? (Thanks in advance for any help)