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Topic: Potassium Iodide + Iron (III) Chloride  (Read 9478 times)

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Offline Rhymesayer

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Potassium Iodide + Iron (III) Chloride
« on: April 23, 2007, 06:02:57 PM »
I cant seem to figure out the rest of this equation. The question is, Iron (III) Chloride reacts with Potassium Iodide to form free Iodine (I2) as one of the products and Iron (II) Chloride as another product. I need the balanced equation, the total ionic and the net ionic. I can most likely figure out the total and net but I cant figure out the balanced equation for it. Help please thanks.
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Offline Borek

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Re: Potassium Iodide + Iron (III) Chloride
« Reply #1 on: April 23, 2007, 06:06:41 PM »
Identify both half reactions - reduction and oxidation.
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Offline UnintentionalChaos

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Re: Potassium Iodide + Iron (III) Chloride
« Reply #2 on: April 28, 2007, 02:42:19 AM »
Use the generic redox method I posted here: http://www.chemicalforums.com/index.php?topic=14101.0

Eliminate spectator ions beforehand to make your work less messy.
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